In a circle with radius 14 , cm,the area of t | vedclass

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(D) The area of a sector is given by the formula: $	ext{Area} = \frac{	heta}{360^\circ} 	imes \pi r^2$.Given: Radius $r = 14 \, cm$,Area $= 77 \, c

Vedclass · Accepted Answer

$45$

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(D) The area of a sector is given by the formula: $	ext{Area} = \frac{	heta}{360^\circ} 	imes \pi r^2$.Given: Radius $r = 14 \, cm$,Area $= 77 \, cm^2$,and $\pi = \frac{22}{7}$.Substituting the values into the formula: $77 = \frac{	heta}{360^\circ} 	imes \frac{22}{7} 	imes 14 	imes 14$.$77 = \frac{	heta}{360^\circ} 	imes 22 	imes 2 	imes 14$.$77 = \frac{	heta}{360^\circ} 	imes 616$.$	heta = \frac{77 	imes 360^\circ}{616}$.$	heta = \frac{27720}{616} = 45^\circ$.Therefore,the angle subtended at the centre is $45^\circ$.

In a circle with radius $14 \, cm$,the area of the minor sector corresponding to minor $\widehat{ACB}$ is $77 \, cm^2$. Then,minor $\widehat{ACB}$ subtends an angle of measure $\dots$ at the centre. (in $^\circ$)

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