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(C) There are $32$ distinct positions for teeth in a human mouth.For each position,there are $2$ possibilities: either a tooth is present or it is abs

Vedclass · Accepted Answer

$2^{32} - 1$

Vedclass · Answer

(C) There are $32$ distinct positions for teeth in a human mouth.For each position,there are $2$ possibilities: either a tooth is present or it is absent.Since there are $32$ such positions,the total number of possible combinations of teeth is $2^{32}$.However,the problem states that there is no person without a tooth,which means we must exclude the case where all $32$ positions are empty.Therefore,the maximum population of the city is $2^{32} - 1$.

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