In a common emitter amplifier,a.c. current gain is $40$ and input resistance is $2 \ k\Omega$. The load resistance is given as $10 \ k\Omega$. Then the voltage gain is

In the study of a transistor as an amplifier,if $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$,where $I_{C}$,$I_{B}$,and $I_{E}$ are the collector,base,and emitter currents respectively,then:

If $R_C$ and $R_B$ are respectively the resistances of the collector and base sides of the circuit,and $\beta$ is the current amplification factor,then the voltage gain of a transistor amplifier in common emitter configuration is

The base current in a transistor circuit changes from $45 \mu A$ to $140 \mu A$. Accordingly, the collector current changes from $0.2 \text{ mA}$ to $4.0 \text{ mA}$. The gain in current is

An oscillator is nothing but an amplifier with

$Assertion$ : In common base configuration, the current gain of the transistor is less than unity.
$Reason$ : The collector terminal is reverse biased for amplification.