In a common emitter transistor amplifier, the output resistance is $500 \text{ k}\Omega$ and the current gain $\beta = 50$. If the power gain of the amplifier is $5 \times 10^6$, what is the input resistance (in $\Omega$)?

An $N-P-N$ transistor conducts when:

$A$ transistor is connected in common emitter configuration. The collector supply is $8 V$ and the voltage drop across a resistor of $800 \Omega$ in the collector circuit is $0.5 V$. If the current gain factor $\alpha$ is $0.96$,the base current is

From the given transfer characteristic of a transistor in $CE$ configuration,the value of power gain of this configuration is $10^x$,for $R_B = 10\,k\Omega$ and $R_C = 1\,k\Omega$. The value of $x$ is $.....$.

In an experiment of $CE$ configuration of $n-p-n$ transistor,the transfer characteristics are observed as given in the figure. If the input resistance is $200 \ \Omega$ and output resistance is $60 \ \Omega$,the voltage gain in this experiment will be:

$A$ transistor is used as a common emitter amplifier with a load resistance $2 \ k\Omega$. The input resistance is $150 \ \Omega$. The base current is changed by $20 \ \mu A$,which results in a change in collector current by $1.5 \ mA$. The voltage gain of the amplifier is