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(D) The power gain $(A_p)$ of a transistor amplifier is given by the product of the current gain $(\beta)$ and the voltage gain $(A_v)$.$A_p = \beta \

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$15000$

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(D) The power gain $(A_p)$ of a transistor amplifier is given by the product of the current gain $(\beta)$ and the voltage gain $(A_v)$.$A_p = \beta 	imes A_v$Voltage gain $(A_v)$ is defined as the product of the current gain $(\beta)$ and the ratio of output resistance $(R_c)$ to input resistance $(R_b)$:$A_v = \beta 	imes \frac{R_c}{R_b}$Given:$\beta = 100$$R_c = 3 \ k\Omega$$R_b = 2 \ k\Omega$Calculating $A_v$:$A_v = 100 	imes \frac{3 \ k\Omega}{2 \ k\Omega} = 100 	imes 1.5 = 150$Now,calculating power gain $(A_p)$:$A_p = \beta 	imes A_v = 100 	imes 150 = 15000$Therefore,the power gain is $15000$.

In a common emitter transistor amplifier,the resistance of the collector is $3 \ k\Omega$. If the current amplification factor is $100$ and the base resistance is $2 \ k\Omega$,then the power gain of the transistor is:

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