In a complexometric titration of a metal ion | vedclass

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Question

(A) Initially,the ligand is consumed by the metal ion to form the complex $(C)$. Since neither the metal ion $(M)$ nor the complex $(C)$ absorbs light

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(A) Initially,the ligand is consumed by the metal ion to form the complex $(C)$. Since neither the metal ion $(M)$ nor the complex $(C)$ absorbs light,the absorbance $(A)$ remains near zero or constant during this phase.After the equivalence point is reached,all metal ions have been converted into the complex. Any further addition of the ligand $(L)$ increases its concentration in the solution.Since the ligand $(L)$ absorbs light,the absorbance $(A)$ starts to increase linearly with the volume of the added ligand $(V)$.Therefore,the plot shows a horizontal line followed by an upward slope,which corresponds to the graph in option $A$.

Column-$I$ (Coordination compound)	Column-$II$ (Central metal atom)
$(a)$ Chlorophyll	$(p)$ Rhodium
$(b)$ Blood pigment	$(q)$ Cobalt
$(c)$ Wilkinson catalyst	$(r)$ Calcium
$(d)$ Vitamin $B_{12}$	$(s)$ Iron
	$(t)$ Magnesium

Similar Questions

Assign the correct code for Column-$I$ and Column-$II$:

Column-$I$ (Coordination compound) Column-$II$ (Central metal atom)

$(a)$ Chlorophyll $(p)$ Rhodium

$(b)$ Blood pigment $(q)$ Cobalt

$(c)$ Wilkinson catalyst $(r)$ Calcium

$(d)$ Vitamin $B_{12}$ $(s)$ Iron

$(t)$ Magnesium

$A$ metal complex absorbed orange light. The colour in which it appears is

Chlorophyll is a

Turnbull's blue is a compound

$CO$ (Carbon monoxide) is a neutral oxide of carbon,but it acts as a very strong field ligand and associates with metals to form complex compounds. These complex compounds are very useful in metallurgical processes. $CO$ is a poisonous gas because:

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