In a compound,atoms of element Y form ccp lat | vedclass

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(A) Let the number of atoms of element $Y$ in the $ccp$ lattice be $n = 4$.The number of tetrahedral voids is $2n = 2 	imes 4 = 8$.Element $X$ occupi

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$X_4Y_3$

Vedclass · Answer

(A) Let the number of atoms of element $Y$ in the $ccp$ lattice be $n = 4$.The number of tetrahedral voids is $2n = 2 	imes 4 = 8$.Element $X$ occupies $2/3$ of the tetrahedral voids,so the number of $X$ atoms $= 8 	imes \frac{2}{3} = \frac{16}{3}$.The ratio of $X:Y$ is $\frac{16}{3} : 4$.Multiplying by $3$,we get the ratio $16:12$,which simplifies to $4:3$.Therefore,the formula of the compound is $X_4Y_3$.

In a compound,atoms of element $Y$ form $ccp$ lattice and those of element $X$ occupy $2/3$ of tetrahedral voids. The formula of the compound will be

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