In a cubic close packing,the unit cell has...
- A$4$ tetrahedral voids each of which is shared by four unit cells.
- B$4$ tetrahedral voids within the unit cell
- C$8$ tetrahedral voids each of which is shared by four unit cells
- D$8$ tetrahedral voids within the unit cells
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$A$ compound is formed by two elements $M$ and $N$. Element $N$ forms a hexagonal closed pack $(HCP)$ array with $2/3$ of the octahedral holes occupied by $M$. The formula of the compound is $....$
The close packing that represents the $ABC ABC......$ order is:
Medium
View SolutionIn a compound,atoms of element $Y$ form a $ccp$ lattice and atoms of element $X$ occupy $2/3$ of the tetrahedral voids. What is the formula of the compound?
Medium
View Solution$A$ crystalline solid is made of $X$,$Y$ and $Z$ elements. Atoms of $X$ form $FCC$ packing; atoms of $Y$ occupy octahedral voids while atoms of $Z$ occupy tetrahedral voids. What will be the simplest formula of the solid if atoms along one body diagonal are removed?
$A$ binary solid has a zinc blende structure with $B$ ions constituting the lattice and $A$ ions occupying $25\%$ of the tetrahedral holes. The formula of the solid is:
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