In a diffraction experiment from a single sli | vedclass

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(B) The linear width of the central maximum in a single-slit diffraction pattern is given by $w = \frac{2 \lambda D}{d}$,where $\lambda$ is the wavele

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distance of the slit from the screen

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(B) The linear width of the central maximum in a single-slit diffraction pattern is given by $w = \frac{2 \lambda D}{d}$,where $\lambda$ is the wavelength,$D$ is the distance from the slit to the screen,and $d$ is the slit width.The angular width of the central maximum is defined as the angle subtended by the central maximum at the slit,given by $	heta = \frac{w}{D} = \frac{2 \lambda}{d}$.From this formula,it is clear that the angular width depends only on the wavelength $\lambda$ and the slit width $d$. It does not depend on the distance $D$ between the slit and the screen.

Element	$M^{3+}/M$	$M^{+}/M$
$Al$	$-1.66$	$+0.55$
$Tl$	$+1.26$	$-0.34$

In a diffraction experiment from a single slit,the angular width of the central maxima does $NOT$ depend upon

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