In a diffraction pattern produced by a thin wire,what happens to the fringe width when the diameter of the wire is increased?

Obtain the formulas for the angular width and linear width of the central maximum in a single-slit diffraction experiment.

Light of wavelength $580 \text{ nm}$ is incident normally on a slit of width '$a$'. The distance between the slit and the screen is $2.5 \text{ m}$ and the distance of the second order maximum from the centre of the screen is $14.5 \text{ mm}$ in a diffraction pattern. The value of '$a$' is

Two slits are $1 \,mm$ apart and the screen is located $1 \,m$ away from the slits. $A$ light of wavelength $500 \,nm$ is used. The width of each slit to obtain $10$ maxima of the double slit pattern within the central maximum of the single slit pattern is $\ldots \ldots \ldots \times 10^{-4} \,m$.

If $n$ represents the order of a half-period zone,the area of this zone is approximately proportional to $n^m$,where $m$ is equal to:

If $I_0$ is the intensity of the principal maximum in the single slit diffraction pattern,then what will be the intensity when the slit width is doubled?