In a dihybrid Mendelian cross,how many types | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a dihybrid cross,two pairs of contrasting traits are considered.For a dihybrid cross,the number of phenotypes is calculated by the formula $2^n

Vedclass · Accepted Answer

$9$ and $4$ respectively

Vedclass · Answer

(C) In a dihybrid cross,two pairs of contrasting traits are considered.For a dihybrid cross,the number of phenotypes is calculated by the formula $2^n$,where $n$ is the number of gene pairs. Here,$n = 2$,so phenotypes = $2^2 = 4$.The number of genotypes is calculated by the formula $3^n$. Here,$n = 2$,so genotypes = $3^2 = 9$.Therefore,in a dihybrid Mendelian cross,there are $9$ types of genotypes and $4$ types of phenotypes.

In a dihybrid Mendelian cross,how many types of genotype and phenotype will be obtained $:-$

Similar Questions

The phenotypic ratio of a dihybrid cross is ....

Mendel's Law of Independent Assortment is proven by .....

If $AAbb \times aaBB$,then the phenotypic ratio of its $F_{2}$ progeny will be

In a trihybrid cross,which plant will produce eight types of gametes?

$A$ heterozygous trihybrid plant produces .....

Vedclass Test Series

Exam Paper Generator

Online Exam Module