In a division sum,the divisor is 12 times the | vedclass

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(D) Let the divisor be $D$,quotient be $Q$,and remainder be $R$.Given that $R = 48$.According to the problem,the divisor is $5$ times the remainder,so

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$4848$

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(D) Let the divisor be $D$,quotient be $Q$,and remainder be $R$.Given that $R = 48$.According to the problem,the divisor is $5$ times the remainder,so $D = 5 	imes R = 5 	imes 48 = 240$.Also,the divisor is $12$ times the quotient,so $D = 12 	imes Q$.Substituting the value of $D$,we get $240 = 12 	imes Q$,which implies $Q = 240 / 12 = 20$.The formula for the dividend is: $	ext{Dividend} = (	ext{Divisor} 	imes 	ext{Quotient}) + 	ext{Remainder}$.Substituting the values: $	ext{Dividend} = (240 	imes 20) + 48 = 4800 + 48 = 4848$.

In a division sum,the divisor is $12$ times the quotient and $5$ times the remainder. If the remainder is $48$,then the dividend is:

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