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(A) The angular width of a fringe in a double-slit experiment is given by $	heta = \frac{\lambda}{d}$, where $\lambda$ is the wavelength of light and

Vedclass · Accepted Answer

$0.09$

Vedclass · Answer

(A) The angular width of a fringe in a double-slit experiment is given by $	heta = \frac{\lambda}{d}$, where $\lambda$ is the wavelength of light and $d$ is the slit separation.Since $d$ remains constant, the angular width is directly proportional to the wavelength: $	heta \propto \lambda$.When the apparatus is immersed in a medium of refractive index $\mu$, the wavelength of light changes to $\lambda' = \frac{\lambda}{\mu}$.Therefore, the new angular width $	heta'$ is given by $	heta' = \frac{	heta}{\mu}$.Given $	heta = 0.15^{\circ}$ and $\mu = \frac{5}{3}$, we have:$	heta' = \frac{0.15^{\circ}}{5/3} = 0.15^{\circ} 	imes \frac{3}{5} = 0.03^{\circ} 	imes 3 = 0.09^{\circ}$.

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