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(C) For a first order reaction,the half-life period $(T_{1/2})$ is the time required for the concentration to become half of its initial value.Given t

Vedclass · Accepted Answer

$30$

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(C) For a first order reaction,the half-life period $(T_{1/2})$ is the time required for the concentration to become half of its initial value.Given that the concentration decreases from $0.8 \ M$ to $0.4 \ M$ in $15 \ min$,this represents one half-life,so $T_{1/2} = 15 \ min$.To find the time taken for the concentration to change from $0.1 \ M$ to $0.025 \ M$,we observe the number of half-lives:$0.1 \ M$ $\xrightarrow{T_{1/2}} 0.05 \ M$ $\xrightarrow{T_{1/2}} 0.025 \ M$.This process involves $2$ half-lives.Therefore,the total time taken $= 2 	imes T_{1/2} = 2 	imes 15 \ min = 30 \ min$.

In a first order reaction,the concentration of the reactant decreases from $0.8 \ M$ to $0.4 \ M$ in $15 \ min$. The time taken for the concentration to change from $0.1 \ M$ to $0.025 \ M$ is .......... $min$.

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