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(B) In a nuclear fission process,a heavy nucleus splits into two lighter nuclei. For the process to be energetically favorable and release energy,the

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${E_b} + {E_c} > {E_a}$

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(B) In a nuclear fission process,a heavy nucleus splits into two lighter nuclei. For the process to be energetically favorable and release energy,the total binding energy of the product nuclei must be greater than the binding energy of the parent nucleus. This is because the binding energy per nucleon increases as we move from a heavy nucleus towards the middle of the periodic table (near iron). Therefore,the sum of the binding energies of the daughter nuclei $B$ and $C$ is greater than the binding energy of the parent nucleus $A$. Thus,${E_b} + {E_c} > {E_a}$.

In a nuclear fission process,a nucleus $A$ divides into two nuclei $B$ and $C$. If their binding energies are ${E_a}$,${E_b}$,and ${E_c}$ respectively,which of the following relations is correct?

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