In a gram panchayat meeting,1000 people voted | vedclass

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(D) Let $x$ be the number of people who voted against the resolution in the first round.Total valid votes in the first round $= 1000 - (10 \% 	ext{ o

Vedclass · Accepted Answer

$400$

Vedclass · Answer

(D) Let $x$ be the number of people who voted against the resolution in the first round.Total valid votes in the first round $= 1000 - (10 \% 	ext{ of } 1000) = 900$.Votes in favour $= 900 - x$.Majority by which it was passed $= (900 - x) - x = 900 - 2x$.In the second round,total valid votes $= 1000 - (20 \% 	ext{ of } 1000) = 800$.Opponents increased by $50 \%$,so new opponents $= 1.5x$.Votes in favour $= 800 - 1.5x$.Since the motion was rejected,the majority against it $= 1.5x - (800 - 1.5x) = 3x - 800$.According to the problem,the new majority is $300 \%$ more than the former majority,meaning it is $400 \%$ of the former majority.$3x - 800 = 4 	imes (900 - 2x)$.$3x - 800 = 3600 - 8x$.$11x = 4400$.$x = 400$.Thus,$400$ people voted against the resolution before the discussion.

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