In a group of 14 males and 6 females, 8 males | vedclass

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(B) Let $F$ be the event that the selected person is a female. Let $A$ be the event that the selected person is aged above $40 	ext{ yr}$. We are giv

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$1/2$

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(B) Let $F$ be the event that the selected person is a female. Let $A$ be the event that the selected person is aged above $40 	ext{ yr}$. We are given: Total number of females $n(F) = 6$. Number of females aged above $40 	ext{ yr}$ is $n(A \cap F) = 3$. We need to find the conditional probability $P(A|F)$, which is the probability that the person is aged above $40 	ext{ yr}$ given that the person is a female. The formula for conditional probability is $P(A|F) = \frac{n(A \cap F)}{n(F)}$. Substituting the values: $P(A|F) = \frac{3}{6} = \frac{1}{2}$.

In a group of $14$ males and $6$ females, $8$ males and $3$ females are aged above $40 \text{ yr}$. The probability that a person selected at random from the group is aged above $40 \text{ yr}$, given that the selected person is a female, is:

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