(A) In a meter bridge,the balancing condition is given by $\frac{R_1}{R_2} = \frac{l}{100 - l}$.For the first case,$\frac{X}{Y} = \frac{20}{100 - 20}

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(A) In a meter bridge,the balancing condition is given by $\frac{R_1}{R_2} = \frac{l}{100 - l}$.For the first case,$\frac{X}{Y} = \frac{20}{100 - 20} = \frac{20}{80} = \frac{1}{4}$.So,$\frac{X}{Y} = \frac{1}{4}$,which implies $Y = 4X$.In the second case,we balance $4X$ against $Y$. Let the new null point be at $l \ cm$.Then,$\frac{4X}{Y} = \frac{l}{100 - l}$.Substituting $Y = 4X$ into the equation,we get $\frac{4X}{4X} = \frac{l}{100 - l}$.$1 = \frac{l}{100 - l} \Rightarrow 100 - l = l \Rightarrow 2l = 100 \Rightarrow l = 50 \ cm$.

Class 12 Physics Current Electricity Meter Bridge

Medium

In a meter bridge experiment,a null point is obtained at $20 \ cm$ from one end of the wire when resistance $X$ is balanced against another resistance $Y$. If $X < Y$,then where will be the new position of the null point from the same end,if one decides to balance a resistance of $4X$ against $Y$ (in $cm$)?

AIEEE 2004 All AIEEE

A
$50$
B
$80$
C
$40$
D
$70$

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The resistances in the two arms of the meter bridge are $5 \,\Omega$ and $R \,\Omega$ respectively. When the resistance $R$ is shunted with an equal resistance,the new balance point is at $1.6\,l_1$. The resistance $R$ is .................. $\Omega$.

In a meter bridge experiment,when resistance $X$ is in the left gap and $Y$ is in the right gap,the null point is found at $20 \ cm$ from the left end. If $X < Y$,what will be the new position of the null point from the same end if a resistance of $4X$ is placed in the left gap instead of $X$?

In a meter bridge,two gaps in the metallic strip are connected by $3 \Omega$ and $9 \Omega$ resistors. What should be the value of the shunt that needs to be added in parallel to the $9 \Omega$ resistor to shift the balancing point by $25 \text{ cm}$ (in $\Omega$)?

In a meter bridge experiment,resistances are connected as shown in the figure. The balancing length $l_1$ is $55 \, cm$. Now,an unknown resistance $x$ is connected in series with $P$ and the new balancing length is found to be $75 \, cm$. The value of $x$ is

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