In a mixture of 1 g of H_2 and 8 g of O_2,t | vedclass

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Question

(A) Step $1$: Calculate the number of moles of $H_2$ $(n_{H_2} = \frac{1 \ g}{2 \ g/mol} = 0.5 \ mol)$.Step $2$: Calculate the number of moles of $O_2

Vedclass · Accepted Answer

$0.67$

Vedclass · Answer

(A) Step $1$: Calculate the number of moles of $H_2$ $(n_{H_2} = \frac{1 \ g}{2 \ g/mol} = 0.5 \ mol)$.Step $2$: Calculate the number of moles of $O_2$ $(n_{O_2} = \frac{8 \ g}{32 \ g/mol} = 0.25 \ mol)$.Step $3$: Calculate the mole fraction of $H_2$ $(x_{H_2} = \frac{n_{H_2}}{n_{H_2} + n_{O_2}} = \frac{0.5}{0.5 + 0.25} = \frac{0.5}{0.75} = 0.667)$.

In a mixture of $1 \ g$ of $H_2$ and $8 \ g$ of $O_2$,the mole fraction of hydrogen is

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