In a motor of 120 machine parts,5 % parts wer | vedclass

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(B) Step $1$: Calculate the number of defective parts in the first motor.Number of defective parts $= 5 \% 	ext{ of } 120 = \frac{5}{100} 	imes 120

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(B) Step $1$: Calculate the number of defective parts in the first motor.Number of defective parts $= 5 \% 	ext{ of } 120 = \frac{5}{100} 	imes 120 = 6$.Step $2$: Calculate the number of defective parts in the second motor.Number of defective parts $= 10 \% 	ext{ of } 80 = \frac{10}{100} 	imes 80 = 8$.Step $3$: Calculate the total number of parts and total defective parts.Total parts $= 120 + 80 = 200$.Total defective parts $= 6 + 8 = 14$.Step $4$: Calculate the percentage of defective parts for the two motors combined.Percentage $= \left( \frac{	ext{Total defective parts}}{	ext{Total parts}} ight) 	imes 100 = \left( \frac{14}{200} ight) 	imes 100 = 7 \%$.

In a motor of $120$ machine parts,$5 \%$ parts were defective. In another motor of $80$ machine parts,$10 \%$ parts were defective. For the two motors considered together,the percentage of defective machine parts was (in $\%$)

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