In a nuclear fission process,a high mass nuclide $(A \approx 236)$ with binding energy $7.6 \ MeV/\text{nucleon}$ dissociates into two middle mass nuclides $(A \approx 118)$,each having a binding energy of $8.6 \ MeV/\text{nucleon}$. The energy released in the process is $MeV$.

  • A
    $236$
  • B
    $623$
  • C
    $359$
  • D
    $417$

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If the energy released per fission of a ${ }_{92}^{235} U$ nucleus is $200 \text{ MeV}$, the energy released in the fission of $0.1 \text{ kg}$ of ${ }_{92}^{235} U$ in kilowatt-hour is:

In the nuclear fusion reaction ${ }_1 H^2+{ }_1 H^3 \rightarrow{ }_2 He^4+n$, if the repulsive potential energy between the two nuclei is $2.07 \times 10^{-14} \,J$, then the temperature at which the gases must be heated to initiate the reaction is (Boltzmann constant $k = 1.38 \times 10^{-23} \,JK^{-1}$).

Calculate the power output of a ${}_{92}^{235}U$ reactor, if it takes $30 \, \text{days}$ to consume $2 \, \text{kg}$ of fuel, and if each fission releases $185 \, \text{MeV}$ of usable energy. (Given: Avogadro's number $= 6 \times 10^{23} \, \text{mol}^{-1}$) .......... $\text{MW}$ (in $.3$)

Assertion : Energy is released in nuclear fission.
Reason : Total binding energy of the fission fragments is larger than the total binding energy of the parent nucleus.

The number of neutrons released when $_{92}U^{235}$ undergoes fission by absorbing $_0n^1$ and $(_{56}Ba^{144} + _{36}Kr^{89})$ are formed,is

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