In an Ostwald process:NH_3 + O_2 xrightarrow[ | vedclass

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(B) The reactions in the Ostwald process are:$4NH_3 + 5O_2 \xrightarrow[Pt]{\Delta} 4NO + 6H_2O$$2NO + O_2 	o 2NO_2$$3NO_2 + H_2O 	o 2HNO_3 + NO$Her

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$x$ and $y$ are acidic oxides

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(B) The reactions in the Ostwald process are:$4NH_3 + 5O_2 \xrightarrow[Pt]{\Delta} 4NO + 6H_2O$$2NO + O_2 	o 2NO_2$$3NO_2 + H_2O 	o 2HNO_3 + NO$Here,$x$ is $NO$,$y$ is $NO_2$,and $z$ is $HNO_3$.$1$. $NO$ $(x)$ is paramagnetic due to the presence of an odd number of electrons.$2$. $NO_2$ $(y)$ and $HNO_3$ $(z)$ are acidic,but $NO$ $(x)$ is a neutral oxide. Therefore,the statement that $x$ and $y$ are acidic oxides is incorrect.$3$. $HNO_3$ $(z)$ is a strong oxidising agent.$4$. Both $NO_2$ and $HNO_3$ are acidic in nature.

In an Ostwald process:
$NH_3 + O_2 \xrightarrow[Pt]{\Delta} x + H_2O$
$x + O_2 \to y$
$y + H_2O (excess) \to x + z$
The incorrect option is:

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In an Ostwald process:$NH_3 + O_2 \xrightarrow[Pt]{\Delta} x + H_2O$$x + O_2 \to y$$y + H_2O (excess) \to x + z$The incorrect option is: