(A) The current $I$ flowing through the potentiometer wire is given by the Ohm's law: $I = \frac{V_{total}}{R_{total}} = \frac{5 \ V}{50 \ \Omega + 45

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(A) The current $I$ flowing through the potentiometer wire is given by the Ohm's law: $I = \frac{V_{total}}{R_{total}} = \frac{5 \ V}{50 \ \Omega + 450 \ \Omega} = \frac{5}{500} \ A = 0.01 \ A$.The potential drop across the entire wire is $V_{wire} = I \times R_{wire} = 0.01 \ A \times 50 \ \Omega = 0.5 \ V$.The potential gradient $k$ (potential drop per unit length) is $k = \frac{V_{wire}}{L} = \frac{0.5 \ V}{10 \ m} = 0.05 \ V/m$.The emf $E$ of the unknown battery is balanced at a length $l = 450 \ cm = 4.5 \ m$.Therefore,$E = k \times l = 0.05 \ V/m \times 4.5 \ m = 0.225 \ V$.

Class 12 Physics Current Electricity Potentiometer

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In a potentiometer,a wire of length $10 \ m$ having resistance $50 \ \Omega$ is used. $A$ battery of $5 \ V$ and a resistor of $450 \ \Omega$ are connected in series to the wire. If an unknown battery of emf $E$ balances the potentiometer at $450 \ cm$,then the value of $E$ is (in $V$)

AP EAMCET 2018 All AP EAMCET

A
$0.225$
B
$1.25$
C
$2.25$
D
$0.0225$

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Current Electricity

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DifficultAP EAMCET 2020

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Explain the comparison of the electromotive force (emf) of two cells using a potentiometer with a necessary diagram.

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$A$ cell,shunted by an $8 \; \Omega$ resistance,is balanced across a potentiometer wire of length $3 \; m$. The balancing length is $2 \; m$ when the cell is shunted by a $4 \; \Omega$ resistance. The value of internal resistance of the cell will be $\dots \; \Omega$.

MediumJEE MAIN 2022

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In a potentiometer,a wire of length $10 \ m$ having resistance $50 \ \Omega$ is used. $A$ battery of $5 \ V$ and a resistor of $450 \ \Omega$ are connected in series to the wire. If an unknown battery of emf $E$ balances the potentiometer at $450 \ cm$,then the value of $E$ is (in $V$)

Similar Questions

For comparing the $e.m.f.$'s of two cells with a potentiometer,a standard cell is used to develop a potential gradient along the wires. Which of the following possibilities would make the experiment unsuccessful?

In a potentiometer experiment, the balancing length with a cell is $560 \, cm$. When an external resistance of $10 \, \Omega$ is connected in parallel to the cell, the balancing length changes by $60 \, cm$. Find the internal resistance of the cell.

Explain the comparison of the electromotive force (emf) of two cells using a potentiometer with a necessary diagram.

$A$ cell,shunted by an $8 \; \Omega$ resistance,is balanced across a potentiometer wire of length $3 \; m$. The balancing length is $2 \; m$ when the cell is shunted by a $4 \; \Omega$ resistance. The value of internal resistance of the cell will be $\dots \; \Omega$.

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