In a queue of children,Kashish is 5^{th} from | vedclass

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(C) Let the initial positions be: Kashish is $5^{th}$ from the left and Mona is $6^{th}$ from the right.After interchanging,Kashish becomes $13^{th}$

Vedclass · Accepted Answer

$14$

Vedclass · Answer

(C) Let the initial positions be: Kashish is $5^{th}$ from the left and Mona is $6^{th}$ from the right.After interchanging,Kashish becomes $13^{th}$ from the left.Since Kashish is now at the position where Mona was initially,the total number of children in the queue is given by: $(	ext{Kashish's new position from left} + 	ext{Mona's original position from right} - 1) = (13 + 6 - 1) = 18$.Now,we need to find Mona's new position from the right. Mona is now at the position where Kashish was initially ($5^{th}$ from the left).Using the formula: $	ext{Position from right} = (	ext{Total children} - 	ext{Position from left} + 1)$.Mona's new position from the right = $(18 - 5 + 1) = 14^{th}$.

In a queue of children,Kashish is $5^{th}$ from the left and Mona is $6^{th}$ from the right. When they interchange their places among themselves,Kashish becomes $13^{th}$ from the left. Then,what will be Mona's position from the right (in $^{th}$)?

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