In a radioactive reaction _{92}X^{232} to _{8 | vedclass

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(A) In a radioactive decay process,the number of $\alpha$-particles emitted is calculated by the change in the mass number divided by $4$.Let $n_{\alp

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(A) In a radioactive decay process,the number of $\alpha$-particles emitted is calculated by the change in the mass number divided by $4$.Let $n_{\alpha}$ be the number of $\alpha$-particles emitted.The mass number changes from $A = 232$ to $A' = 204$.The formula for the number of $\alpha$-particles is $n_{\alpha} = \frac{A - A'}{4}$.Substituting the values: $n_{\alpha} = \frac{232 - 204}{4} = \frac{28}{4} = 7$.Thus,$7$ $\alpha$-particles are emitted.

In a radioactive reaction $_{92}X^{232} \to _{82}Y^{204}$,the number of $\alpha$-particles emitted is:

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