In a reaction between zinc and iodine,in whic | vedclass

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(C) The chemical equation for the reaction is: $Zn(s) + I_2(s) \rightarrow ZnI_2(s)$.In this reaction,the oxidation state of $Zn$ increases from $0$ t

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Zinc atom

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(C) The chemical equation for the reaction is: $Zn(s) + I_2(s) \rightarrow ZnI_2(s)$.In this reaction,the oxidation state of $Zn$ increases from $0$ to $+2$,which means the $Zn$ atom is oxidised.The oxidation state of $I$ decreases from $0$ to $-1$,which means $I_2$ is reduced.Therefore,the $Zn$ atom is being oxidised.

In a reaction between zinc and iodine,in which zinc iodide is formed,what is being oxidised?

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