In the reaction CH_2=CH_2 xrightarrow{HOCl} M | vedclass

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(B) The reaction of ethene $(CH_2=CH_2)$ with hypochlorous acid $(HOCl)$ follows an electrophilic addition mechanism to form ethylene chlorohydrin $(C

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$Cl-CH_2-CH_2-OH$ and $aq. NaHCO_3$

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(B) The reaction of ethene $(CH_2=CH_2)$ with hypochlorous acid $(HOCl)$ follows an electrophilic addition mechanism to form ethylene chlorohydrin $(Cl-CH_2-CH_2-OH)$,which is molecule $M$.Ethylene chlorohydrin then undergoes hydrolysis in the presence of a mild base like aqueous sodium bicarbonate $(aq. NaHCO_3)$,which acts as reagent $R$,to produce ethylene glycol $(HO-CH_2-CH_2-OH)$.

In the reaction $CH_2=CH_2$ $\xrightarrow{HOCl} M$ $\xrightarrow{R} HO-CH_2-CH_2-OH$,where $M$ is a molecule and $R$ is a reagent,$M$ and $R$ are:

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