In a school,442 boys and 374 girls have been | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Number of boys $= 442$; Number of girls $= 374$.To find the largest possible equal number of students in each class,we calculate the $HCF$ of $442

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(D) Number of boys $= 442$; Number of girls $= 374$.To find the largest possible equal number of students in each class,we calculate the $HCF$ of $442$ and $374$.Prime factorization of $442 = 2 	imes 13 	imes 17$.Prime factorization of $374 = 2 	imes 11 	imes 17$.$HCF(442, 374) = 2 	imes 17 = 34$.So,each class contains $34$ students.Number of classes of boys $= 442 \div 34 = 13$.Number of classes of girls $= 374 \div 34 = 11$.Total number of classes $= 13 + 11 = 24$.

In a school,$442$ boys and $374$ girls have been divided into the largest possible equal classes,so that each class of boys numbers the same as each class of girls. What is the number of classes?

Similar Questions

The $HCF$ and $LCM$ of two numbers are $36$ and $756$ respectively. Find the possible pair of numbers.

The greatest number that divides $43, 91,$ and $183$ so as to leave the same remainder in each case is:

Find the sum of the numbers between $500$ and $700$ such that when they are divided by $6, 8$ and $12$ it leaves no remainder.

The $LCM$ of two numbers is $495$ and their $HCF$ is $5.$ If the sum of the numbers is $100,$ then their difference is

The least number which when divided by $5, 6, 7$ and $8$ leaves $3$ as a remainder,but when divided by $9$ leaves no remainder,is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module