In a series L-C circuit,if L=10^{-3} ,H and C | vedclass

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(C) Given: $L = 10^{-3} \,H$,$C = 3 	imes 10^{-7} \,F$,$f = 50 \,Hz$.Angular frequency $\omega = 2 \pi f = 2 \pi 	imes 50 = 100 \pi \,rad/s$.Inducti

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$\frac{10^5}{3 \pi}-\frac{\pi}{10}$

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(C) Given: $L = 10^{-3} \,H$,$C = 3 	imes 10^{-7} \,F$,$f = 50 \,Hz$.Angular frequency $\omega = 2 \pi f = 2 \pi 	imes 50 = 100 \pi \,rad/s$.Inductive reactance $X_L = \omega L = (100 \pi) 	imes 10^{-3} = 0.1 \pi \, \Omega$.Capacitive reactance $X_C = \frac{1}{\omega C} = \frac{1}{100 \pi 	imes 3 	imes 10^{-7}} = \frac{10^7}{300 \pi} = \frac{10^5}{3 \pi} \, \Omega$.Since it is a series $L-C$ circuit,the impedance $Z = |X_L - X_C|$.$Z = |0.1 \pi - \frac{10^5}{3 \pi}|$.Since $\frac{10^5}{3 \pi} \approx 10610 \, \Omega$ and $0.1 \pi \approx 0.314 \, \Omega$,the impedance is $Z = \frac{10^5}{3 \pi} - 0.1 \pi = \frac{10^5}{3 \pi} - \frac{\pi}{10} \, \Omega$.

In a series $L-C$ circuit,if $L=10^{-3} \,H$ and $C=3 \times 10^{-7} \,F$ is connected to a $100 \,V, 50 \,Hz$ a.c. source,the impedance of the circuit is ...........

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