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(B) In a single-slit diffraction experiment,the linear width of the central maxima is given by the formula $\beta = \frac{2 \lambda D}{a}$,where $\lam

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increases but becomes less bright

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(B) In a single-slit diffraction experiment,the linear width of the central maxima is given by the formula $\beta = \frac{2 \lambda D}{a}$,where $\lambda$ is the wavelength of light,$D$ is the distance of the screen from the slit,and $a$ is the width of the slit.From the formula,it is clear that the width of the central maxima $\beta$ is inversely proportional to the slit width $a$ $(\beta \propto 1/a)$.Therefore,if the width of the slit $a$ is reduced,the linear width of the central maxima $\beta$ will increase.Additionally,as the slit width decreases,the amount of light passing through the slit decreases,which results in a reduction in the intensity of the central maxima,making it less bright.

In a single-slit diffraction experiment,if the width of the slit is reduced,what happens to the linear width of the principal (central) maxima?

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