In a single slit diffraction of light of wavelength $\lambda$ by a slit of width $e$,the size of the central maximum on a screen at a distance $b$ is

$A$ plane wavefront of monochromatic light is incident normally on a narrow slit. $A$ diffraction pattern is formed on a screen. What is the phase difference between the waves originating from the top and bottom edges of the slit at the position of the first minimum?

$A$ circular disc is placed in front of a narrow source. When the point of observation is $2 \, m$ from the disc,it covers the first $HPZ$. The intensity at this point is $I$. When the point of observation is $25 \, cm$ from the disc,the intensity will be:

If we observe the single slit Fraunhofer diffraction with wavelength $\lambda$ and slit width $e$,the width of the central maxima is $2\theta$. On decreasing the slit width for the same $\lambda$,what happens to $\theta$?

$A$ parallel beam of monochromatic light is incident on a narrow rectangular slit of width $1\,mm$. When the diffraction pattern is seen on a screen placed at a distance of $2\,m$, the width of the principal maxima is found to be $2.5\,mm$. The wavelength of light is $.............\mathring{A}$.

In Fraunhofer diffraction due to a single slit,find the path difference for the $n^{th}$ order minimum.