In a step-up transformer, the turn ratio is 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given: Turn ratio $\frac{N_p}{N_s} = \frac{1}{10}$, Secondary resistance $R_s = 200 \, \Omega$, Secondary current $I_s = 0.5 \, A$.First, calculat

Vedclass · Accepted Answer

$10 \, V, 5 \, A$

Vedclass · Answer

(B) Given: Turn ratio $\frac{N_p}{N_s} = \frac{1}{10}$, Secondary resistance $R_s = 200 \, \Omega$, Secondary current $I_s = 0.5 \, A$.First, calculate the secondary voltage $(V_s)$ using Ohm's law:$V_s = I_s 	imes R_s = 0.5 \, A 	imes 200 \, \Omega = 100 \, V$.Using the transformer ratio formula $\frac{V_s}{V_p} = \frac{N_s}{N_p}$:$\frac{100}{V_p} = \frac{10}{1} \implies V_p = 10 \, V$.Using the current relation $\frac{I_p}{I_s} = \frac{N_s}{N_p}$:$\frac{I_p}{0.5} = \frac{10}{1} \implies I_p = 5 \, A$.Thus, the primary voltage is $10 \, V$ and the primary current is $5 \, A$.

In a step-up transformer, the turn ratio is $1:10$. A resistance of $200 \, \Omega$ connected across the secondary is drawing a current of $0.5 \, A$. What is the primary voltage and current?

Similar Questions

In a transformer,the number of turns in the primary coil is $140$ and that in the secondary coil is $280$. If the current in the primary coil is $4 \ A$,then the current in the secondary coil is (in $A$):

$A$ step-down transformer has a turns ratio of $20:1$. If $8 \, V$ is applied across a $0.4 \, \Omega$ secondary coil, then the primary current will be: (in $ \, A$)

Write important uses of transformer.

$A$ transformer consisting of $300$ turns in the primary and $150$ turns in the secondary gives output power of $2.2\, kW$. If the current in the secondary coil is $10\, A$,then the input voltage and current in the primary coil are

The instrument which works on the principle of mutual inductance is

Vedclass Test Series

Exam Paper Generator

Online Exam Module