In a surface tension experiment with a capillary tube,water rises up to $0.1\, m$. If the same experiment is repeated on an artificial satellite,which is revolving around the Earth,water will rise in the capillary tube up to a height of:

$A$ capillary tube of radius '$r$' is immersed in water and water rises to a height of '$h$'. The mass of water in the capillary tube is $5 \times 10^{-3} \ kg$. The same capillary tube is now immersed in a liquid whose surface tension is $\sqrt{2}$ times the surface tension of water. The angle of contact between the capillary tube and this liquid is $45^{\circ}$. The mass of liquid which rises into the capillary tube now is (in $kg$):

$A$ glass rod of radius $r_1$ is inserted symmetrically into a vertical capillary tube of radius $r_2$ $(r_1 < r_2)$ such that their lower ends are at the same level. The arrangement is dipped in water. The height to which water will rise into the tube will be ($\rho =$ density of water,$T =$ surface tension of water,$g =$ acceleration due to gravity).

$A$ capillary tube of radius $r$ is initially just vertically completely immersed inside a liquid of angle of contact $0^{\circ}$. If the tube is slowly raised,then the relation between the radius of curvature of the meniscus inside the capillary tube and the displacement $(h)$ of the tube can be represented by:

$A$ $20 cm$ long capillary tube is dipped vertically in water and the liquid rises up to $10 cm$. If the entire system is kept in a freely falling platform, the length of the water column in the tube will be (in $cm$)

Water rises up to a height $h$ in a capillary tube on the surface of the Earth in a stationary condition. The value of $h$ increases if this tube is taken: