In a survey of 60 people,it was found that 25 | vedclass

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(A) Let $H, T,$ and $I$ be the sets of people who read newspapers $H, T,$ and $I$ respectively.Given:$n(H) = 25, n(T) = 26, n(I) = 26$$n(H \cap I) = 9

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$52$

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(A) Let $H, T,$ and $I$ be the sets of people who read newspapers $H, T,$ and $I$ respectively.Given:$n(H) = 25, n(T) = 26, n(I) = 26$$n(H \cap I) = 9, n(H \cap T) = 11, n(T \cap I) = 8$$n(H \cap T \cap I) = 3$We need to find the number of people who read at least one newspaper,which is $n(H \cup T \cup I)$.Using the formula:$n(H \cup T \cup I) = n(H) + n(T) + n(I) - n(H \cap T) - n(T \cap I) - n(H \cap I) + n(H \cap T \cap I)$$n(H \cup T \cup I) = 25 + 26 + 26 - 11 - 8 - 9 + 3$$n(H \cup T \cup I) = 77 - 28 + 3$$n(H \cup T \cup I) = 52$Thus,$52$ people read at least one of the newspapers.

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