In a transistor configuration,the $\beta$-parameter is defined as:

The power gain and voltage gain of a transistor connected in common emitter configuration are $1800$ and $60$ respectively. If the change in the emitter current is $0.62 \text{ mA}$, then the change in the collector current is: (in $\text{ mA}$)

In the given common-emitter circuit, an $npn$ transistor with $\beta = 100$ is connected. What is the output voltage of the amplifier?

The graph of the input characteristic of a common emitter amplifier is:

In the given common emitter transistor circuit,the base current is $I_B = 40 \, \mu A$. Determine the base-emitter voltage $V_{BE}$. (in $, V$)

For a transistor,$\alpha$ and $\beta$ are given as $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$. Then the correct relation between $\alpha$ and $\beta$ is: