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(B) Given,maximum magnetic field,$B_0 = 1.26 	imes 10^{-4} \ T$ and permeability of free space,$\mu_0 = 1.26 	imes 10^{-6} \ H/m$. The speed of ligh

Vedclass · Accepted Answer

$1.89 	imes 10^6 \ W/m^2$

Vedclass · Answer

(B) Given,maximum magnetic field,$B_0 = 1.26 	imes 10^{-4} \ T$ and permeability of free space,$\mu_0 = 1.26 	imes 10^{-6} \ H/m$. The speed of light is $c = 3 	imes 10^8 \ m/s$. The intensity $I$ of an electromagnetic wave is given by the formula: $I = \frac{1}{2} \frac{B_0^2 c}{\mu_0}$ Substituting the values: $I = \frac{1}{2} 	imes \frac{(1.26 	imes 10^{-4})^2 	imes 3 	imes 10^8}{1.26 	imes 10^{-6}}$ $I = \frac{1}{2} 	imes \frac{1.26 	imes 1.26 	imes 10^{-8} 	imes 3 	imes 10^8}{1.26 	imes 10^{-6}}$ $I = \frac{1}{2} 	imes 1.26 	imes 3 	imes 10^2 	imes 10^6$ $I = 0.63 	imes 3 	imes 10^6 = 1.89 	imes 10^6 \ W/m^2$.

In a travelling plane electromagnetic wave,the maximum magnetic field is $1.26 \times 10^{-4} \ T$. The intensity of the wave is (Assume,$\mu_0 = 1.26 \times 10^{-6} \ H/m$)

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