In a triangle $ABC$ with usual notations,if $\tan \left(\frac{B-C}{2}\right) = x \cot \frac{A}{2}$,then $x =$

  • A
    $\frac{c-a}{c+a}$
  • B
    $\frac{a-b}{a+b}$
  • C
    $\frac{b-c}{b+c}$
  • D
    $\frac{a+b}{a-b}$

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