In a triangle ABC,right-angled at C,the value | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given a right-angled triangle $ABC$ with the right angle at $C$.Let $a, b,$ and $c$ be the lengths of sides $BC, CA,$ and $AB$ respectively.From t

Vedclass · Accepted Answer

$\frac{c^2}{ab}$

Vedclass · Answer

(D) Given a right-angled triangle $ABC$ with the right angle at $C$.Let $a, b,$ and $c$ be the lengths of sides $BC, CA,$ and $AB$ respectively.From the Pythagoras theorem,we have $c^2 = a^2 + b^2$.In the right-angled triangle $ABC$:$	an A = \frac{	ext{opposite}}{	ext{adjacent}} = \frac{BC}{AC} = \frac{a}{b}$$	an B = \frac{	ext{opposite}}{	ext{adjacent}} = \frac{AC}{BC} = \frac{b}{a}$Therefore,$	an A + 	an B = \frac{a}{b} + \frac{b}{a}$$= \frac{a^2 + b^2}{ab}$Since $a^2 + b^2 = c^2$,we get:$= \frac{c^2}{ab}$

In a triangle $ABC$,right-angled at $C$,the value of $\tan A + \tan B$ is

Similar Questions

Let $a=BC, b=CA, c=AB$ be the side lengths of a $\triangle ABC$ and $m$ be the length of the median through $A$. If $a=8, b-c=2, m=6$,then the nearest integer to $b$ is

If the sides of a triangle are in the ratio $3 : 7 : 8,$ then $R : r$ is equal to

If in a $\Delta ABC$,$\cos A + 2\cos B + \cos C = 2$,then $a, b, c$ are in

In $\triangle ABC$, if $\angle A = 90^{\circ}$, then $\sin(B - C) =$

In any $\triangle ABC$, the expression $\frac{(a+b+c)(b+c-a)(c+a-b)(a+b-c)}{4b^2c^2}$ is equal to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module