In a Young's double slit experiment,the angular width of a fringe formed on a distant screen is $0.1 \ radian$. Find the distance between the two slits in $\mu m$,if the wavelength of light used is $6000 \ \mathring{A}$.

Obtain the formula for the path difference at a point on the screen in Young's double-slit experiment in terms of $x$,$d$,and $D$.

Two identical narrow slits $S_1$ and $S_2$ are illuminated by light of wavelength $\lambda$ from a point source $P$. If,as shown in the diagram,the light is then allowed to fall on a screen,and if $n$ is a positive integer,the condition for destructive interference at $Q$ is that

In an interference experiment, the third bright fringe is obtained at a point on the screen with light of wavelength $700 \, nm$. What should be the wavelength of the light source in order to obtain the $5^{th}$ bright fringe at the same point (in $nm$)?

In $YDSE$ experiment,the $4^{\text{th}}$ dark band is formed opposite to one of the slits. The wavelength of light used is ($d=$ distance between the slits,$D=$ distance between source and the screen)

In Young's double slit experiment, two slits $S_1$ and $S_2$ are $d$ distance apart and the separation from slits to screen is $D$. If two transparent slabs of equal thickness $t = 0.1 \text{ mm}$ but refractive indices $\mu_1 = 1.51$ and $\mu_2 = 1.55$ are introduced in the path of the beam $(\lambda = 4000 \text{ Å})$ from $S_1$ and $S_2$ respectively, the central bright fringe will shift by how many fringes?