(B) The given peptide is a pentapeptide,which consists of $5$ amino acid residues: $\text{alanine}$,$\text{glycine}$,$\text{leucine}$,$\text{alanine}$

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(B) The given peptide is a pentapeptide,which consists of $5$ amino acid residues: $\text{alanine}$,$\text{glycine}$,$\text{leucine}$,$\text{alanine}$,and $\text{valine}$.In a polypeptide chain,the number of peptide linkages is always $(n-1)$,where $n$ is the number of amino acid residues.Here,$n = 5$,so the number of peptide linkages $= 5 - 1 = 4$.