In an AP if a = -7.2, d = 3.6, a_{n} = 7.2, t | vedclass

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(B) The formula for the $n^{th}$ term of an $AP$ is $a_{n} = a + (n - 1)d$.Given values are $a = -7.2$,$d = 3.6$,and $a_{n} = 7.2$.Substituting these

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$5$

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(B) The formula for the $n^{th}$ term of an $AP$ is $a_{n} = a + (n - 1)d$.Given values are $a = -7.2$,$d = 3.6$,and $a_{n} = 7.2$.Substituting these values into the formula:$7.2 = -7.2 + (n - 1)(3.6)$Adding $7.2$ to both sides:$7.2 + 7.2 = (n - 1)(3.6)$$14.4 = (n - 1)(3.6)$Dividing both sides by $3.6$:$\frac{14.4}{3.6} = n - 1$$4 = n - 1$$n = 4 + 1$$n = 5$

In an $AP$ if $a = -7.2, d = 3.6, a_{n} = 7.2,$ then $n$ is

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