In an $n-p-n$ transistor amplifier,the collector current is $8 \ mA$. If $80 \%$ of the electrons from the emitter reach the collector,then ($\alpha$ and $\beta$ are current ratios):

In a $P-N-P$ transistor,the emitter has ....... as majority carriers and the base has ....... as majority carriers.

The dc common emitter current gain of an $n-p-n$ transistor is $50$. The potential difference applied across the collector and emitter of a transistor used in $CE$ configuration is $V_{CE} = 2 \ V$. If the collector resistance $R_{C} = 4 \ k\Omega$,the base current $(I_{B})$ and the collector current $(I_{C})$ are:

The current gain of a transistor in common emitter configuration is $80$. The resistances in collector and base sides of the circuit are $5 \text{ k}\Omega$ and $1 \text{ k}\Omega$ respectively. If the input voltage is $2 \text{ mV}$, the output voltage is: (in $\text{ V}$)

The load resistance and the base-emitter voltage of a transistor in $CE$ configuration are $5 \ k\Omega$ and $0.02 \ V$ respectively. If the collector current is $2 \ mA$,then its voltage gain is

When an $n-p-n$ junction transistor is used as an amplifier in common emitter mode,