In an $LCR$ series circuit, the potential difference across the terminals of the inductor, capacitor and resistor is $60 \text{ V}$, $30 \text{ V}$ and $40 \text{ V}$ respectively. Then the supply voltage will be equal to (in $\text{ V}$)

With an increase in the frequency of an $a.c.$ supply,the impedance of an $LCR$ series circuit:

$A$ capacitor,an inductor,and an electric bulb are connected in series to an a.c. supply of variable frequency. As the frequency of the supply is increased gradually,the electric bulb is found to

An a.c. source is applied to a series $LR$ circuit with $X_L = 3R$ and the power factor is $X_1$. Now,a capacitor with $X_C = R$ is added in series to the $LR$ circuit and the power factor is $X_2$. The ratio $X_1$ to $X_2$ is

In a series $L-C-R$ circuit,the inductive reactance is twice the resistance and the capacitive reactance is $1/3$ rd of the inductive reactance. The power factor of the circuit is

$A$ capacitance of $\left(\frac{10^{-3}}{2 \pi}\right) F$,an inductance of $\left(\frac{100}{\pi}\right) mH$,and a resistance of $10 \Omega$ are connected in series with an $AC$ voltage source of $220 V, 50 Hz$. The phase angle of the circuit is (in $^{\circ}$)