In an $NPN$ transistor, the collector current is $28 \text{ mA}$. If $80\%$ of the electrons emitted by the emitter reach the collector, what is the base current in $\text{mA}$ (in $\text{ mA}$)?

For the given Common Emitter $(CE)$ transistor circuit,the base current is $I_B = 0.04 \text{ mA}$. If the current gain $\beta = 100$ and the collector-emitter voltage $V_{CE} = 12 \text{ V}$,find the value of the collector resistance $R_C$ in $\text{k}\Omega$.

If $\alpha$ and $\beta$ are the current gains in the $CB$ and $CE$ configurations respectively of the transistor circuit,then $\frac{\beta - \alpha}{\alpha \beta} = $

When the transistor is used as an amplifier,

The collector supply voltage is $6 \text{ V}$ and a voltage drop across a resistor of $600 \Omega$ in the collector circuit is $0.6 \text{ V}$,in a circuit of a transistor connected in common emitter mode. If the current gain is $20$,then the base current is: (in $\text{ mA}$)

The typical output characteristics curve for a transistor working in the common-emitter configuration is shown in the figure. The estimated current gain from the figure is