In an a.c. circuit,the voltage applied is E = | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $KEY$ $CONCEPT$: The average power consumed in an $a.c.$ circuit is given by the formula: $P = E_{rms} I_{rms} \cos \phi$.Given:Voltage $E = E_o \

Vedclass · Accepted Answer

$P = 0$

Vedclass · Answer

(C) $KEY$ $CONCEPT$: The average power consumed in an $a.c.$ circuit is given by the formula: $P = E_{rms} I_{rms} \cos \phi$.Given:Voltage $E = E_o \sin \omega t$Current $I = I_o \sin \left( \omega t - \frac{\pi}{2} ight)$Comparing these with the standard forms $E = E_o \sin \omega t$ and $I = I_o \sin (\omega t - \phi)$,we find the phase difference $\phi = \frac{\pi}{2}$.Substituting the value of $\phi$ into the power formula:$P = E_{rms} I_{rms} \cos \left( \frac{\pi}{2} ight)$Since $\cos \left( \frac{\pi}{2} ight) = 0$,the power consumption is:$P = E_{rms} I_{rms} 	imes 0 = 0$.

In an $a.c.$ circuit,the voltage applied is $E = E_o \sin \omega t$. The resulting current in the circuit is $I = I_o \sin \left( \omega t - \frac{\pi}{2} \right)$. The power consumption in the circuit is given by:

Similar Questions

Power factor of an ideal choke coil (i.e.,$R=0$) is

$A$ sinusoidal alternating current of peak value $I_0$ passes through a heater of resistance $R$. What is the mean power output of the heater?

When a voltage $V = V_0 \cos \omega t$ is applied across a resistor of resistance $R$,the average power dissipated per cycle in the resistor is given by

$A$ sinusoidal $AC$ current flows through a resistor of resistance $R$. If the peak current is $I_p$,then the power dissipated is

$(a)$ For circuits used for transporting electric power, a low power factor implies large power loss in transmission. Explain.
$(b)$ Power factor can often be improved by the use of a capacitor of appropriate capacitance in the circuit. Explain.

Vedclass Test Series

Exam Paper Generator

Online Exam Module