In an apparatus, the electric field was found | vedclass

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Question

(B) The relationship between the amplitude of the electric field $(E_0)$ and the amplitude of the magnetic field $(B_0)$ in an electromagnetic wave is

Vedclass · Accepted Answer

$6 	imes 10^{-8} 	ext{ T}$

Vedclass · Answer

(B) The relationship between the amplitude of the electric field $(E_0)$ and the amplitude of the magnetic field $(B_0)$ in an electromagnetic wave is given by the equation: $c = \frac{E_0}{B_0}$, where $c$ is the speed of light in vacuum $(c \approx 3 	imes 10^8 	ext{ m/s})$.Rearranging the formula to solve for $B_0$, we get: $B_0 = \frac{E_0}{c}$.Given $E_0 = 18 	ext{ V/m}$ and $c = 3 	imes 10^8 	ext{ m/s}$, we substitute these values:$B_0 = \frac{18}{3 	imes 10^8} = 6 	imes 10^{-8} 	ext{ T}$.Thus, the magnitude of the oscillating magnetic field is $6 	imes 10^{-8} 	ext{ T}$.

In an apparatus, the electric field was found to oscillate with an amplitude of $18 \text{ V/m}$. The magnitude of the oscillating magnetic field will be:

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