In an election,there were only two candidates | vedclass

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Question

(C) Let the total number of votes polled be $x$.The candidate who lost secured $40\%$ of the votes.Therefore,the winning candidate secured $(100\% - 4

Vedclass · Accepted Answer

$1490$

Vedclass · Answer

(C) Let the total number of votes polled be $x$.The candidate who lost secured $40\%$ of the votes.Therefore,the winning candidate secured $(100\% - 40\%) = 60\%$ of the votes.The difference in the percentage of votes between the two candidates is $(60\% - 40\%) = 20\%$.According to the problem,this difference is equal to $298$ votes.So,$20\%$ of $x = 298$.$\Rightarrow \frac{20}{100} 	imes x = 298$$\Rightarrow \frac{1}{5} 	imes x = 298$$\Rightarrow x = 298 	imes 5 = 1490$.Thus,the total number of votes polled is $1490$.

In an election,there were only two candidates. One of the candidates secured $40\%$ of the votes and was defeated by the other candidate by $298$ votes. The total number of votes polled is:

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