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Question

(B) The direction of propagation of an electromagnetic wave is given by the direction of the Poynting vector,which is $\overrightarrow{S} = \overright

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negative $y$-axis

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(B) The direction of propagation of an electromagnetic wave is given by the direction of the Poynting vector,which is $\overrightarrow{S} = \overrightarrow{E} 	imes \overrightarrow{B}$.Given,the electric field $\overrightarrow{E} = -E_0 \hat{k}$ (along negative $z$-axis).The magnetic field $\overrightarrow{B} = B_0 \hat{i}$ (along positive $x$-axis).The direction of propagation is $\hat{k}_{prop} = \hat{E} 	imes \hat{B} = (-\hat{k}) 	imes (\hat{i})$.Using the cross product rules for unit vectors ($\hat{i} 	imes \hat{j} = \hat{k}$,$\hat{j} 	imes \hat{k} = \hat{i}$,$\hat{k} 	imes \hat{i} = \hat{j}$),we get:$(-\hat{k}) 	imes \hat{i} = -(\hat{k} 	imes \hat{i}) = -\hat{j}$.Therefore,the direction of propagation is along the negative $y$-axis.

In an electromagnetic wave,at an instant and at a particular position,the electric field is along the negative $z$-axis and the magnetic field is along the positive $x$-axis. Then the direction of propagation of the electromagnetic wave is

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