In an electromagnetic wave,the amplitude of the electric field is $1 \ V/m$. The frequency of the wave is $5 \times 10^{14} \ Hz$. The wave is propagating along the $z$-axis. The average energy density of the electric field,in $J/m^3$,will be:
- A$1.1 \times 10^{-11}$
- B$2.2 \times 10^{-12}$
- C$3.3 \times 10^{-13}$
- D$4.4 \times 10^{-14}$
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Which of the following statements is false regarding the properties of electromagnetic waves?
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View SolutionIf $\vec{E}$ and $\vec{K}$ represent the electric field and propagation vectors of electromagnetic $(EM)$ waves in a vacuum,respectively,then the magnetic field vector $\vec{B}$ is given by: (where $\omega$ is the angular frequency).
An electromagnetic $(EM)$ wave is propagating in a medium with a velocity $\vec{v} = v\hat{i}$. The instantaneous oscillating electric field of this $EM$ wave is along the $+y$ axis. Then the direction of the oscillating magnetic field of the $EM$ wave will be along:
In a plane electromagnetic wave,the electric field oscillates with a frequency $2 \times 10^{10} \,s^{-1}$ and amplitude $40 \,Vm^{-1}$. The energy density due to the electric field is (given $\varepsilon_0 = 8.85 \times 10^{-12} \,Fm^{-1}$):
For plane electromagnetic waves propagating in the positive $Z$-direction,the combination which gives the correct possible direction for $\vec{E}$ and $\vec{B}$ fields respectively is:
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