In an experiment for the determination of the refractive index of glass of a prism by an $i - \delta$ plot,it was found that a ray incident at an angle of $35^o$ suffers a deviation of $40^o$ and emerges at an angle of $79^o$. In that case,which of the following is closest to the maximum possible value of the refractive index?

Light rays from a source are incident on a glass prism of refractive index $\mu$ and prism angle $\alpha$. At near-normal incidence,the angle of deviation of the emerging rays is:

$A$ glass prism having a refractive index $\mu$ is placed in air. If the angle of minimum deviation of the prism is equal to the angle of the prism,what is the value of the angle of the prism?

$A$ ray of light passes through an equilateral glass prism in such a manner that the angle of incidence is equal to the angle of emergence and each of these angles is equal to $\frac{3}{4}$ of the angle of the prism. The angle of deviation is (in $^{\circ}$)

One side of an equilateral prism is painted by a transparent material of refractive index $n_2$. The refractive index of the prism is $1.6$. The minimum value of $n_2$ required for total internal reflection from the painted face is . . . . . . .

$A$ prism is made of glass of unknown refractive index. $A$ parallel beam of light is incident on a face of the prism. The angle of minimum deviation is measured to be $40^{\circ}$. What is the refractive index of the material of the prism? The refracting angle of the prism is $60^{\circ}$. If the prism is placed in water (refractive index $1.33$),predict the new angle of minimum deviation of a parallel beam of light.